Escape all special characters in printf()

Question

Is there an easy way to escape all special characters in the printf() function?

The reason why I would like to know how to do this is because I am print

Answer 1

First of all, '\\0' is a two-character literal, which should really be a two-character string. As for printing all special characters as escape code, you need some more code:

switch (data[i])
{
case '\0':
    printf("\\0");
    break;
case '\n':
    printf("\\n");
    break;

/* Etc. */

default:
    /* Now comes the "hard" part, because not all characters here
     * are actually printable
     */
    if (isprint(data[i]))
        printf("%c", data[i]);  /* Printable character, print it as usual */
    else
        printf("\\x%02x", data[i]); /* Non-printable character, print as hex value */

    break;
}