Remove sublist duplicates including reversed

Question

For example i have following

list = [[\'1\', \'2\'], [\'1\', \'3\'], [\'1\', \'4\'], [\'1\', \'5\'], [\'2\', \'1\'], [\'4\', \'1\'], [\'2\', \'6\']]
         


        

Answer 1

This is similar to solution by @Mehul Gupta, but I think their solution is traversing the list twice if matched: one for checking and one for removing. Instead, we could

the_list = [['1', '2'], ['1', '3'], ['1', '4'], ['1', '5'], ['2', '1'], ['4', '1'], ['2', '6']]
for sub_list in the_list:
    try:
        idx = the_list.index(sub_list[::-1])
    except ValueError:
        continue
    else:
        the_list.pop(idx)

print(the_list)
# [['1', '2'], ['1', '3'], ['1', '4'], ['1', '5'], ['2', '6']]

because it is easier to ask for forgiveness than permission.

Note: Removing elements whilst looping is not a good thing but for this specific problem, it does no harm. In fact, it is better because we do not check the mirrored again; we already removed it.