How do I return an array of struct from a function?

Question

How do I return an array of struct from a function? Here\'s my work; it\'s pretty simple to understand. I\'m unable to return the array items so that it can be used in the

Answer 1

first in this code below

//  n is 0 and n > 2 is false so loop will never execute.
for(n=0;n>2;n++){
        printf(" name: "); gets(items[n].nome);
        printf(" telefone: "); gets(items[n].telefone);
        printf(" age: "); gets(items[n].idade);
    }

next

 items = fun(); // i don't see items declared anywhere

and here

    printf(" name: "); gets(items[n].nome); // surely its not nome
    printf(" telefone: "); gets(items[n].telefone);
    printf(" age: "); gets(items[n].idade); // neither it is idade

Finally solution, you need to use pointers and allocate memory dynamically

Your function becomes something like this, ( see the typo )

//struct Operator fun();
struct Operador * fun(); // if this is what is correct

Allocation

   //struct Operador items[3];
    struct Operador * items = malloc( 3 * sizeof(struct Operador));

and return call

//return items[n];
return items;

and at the end

free(items);

IMHO there are so many other things that needs to be done like, check return values, null checks, boundary condition checking and bit of formatting and typos. I'll leave it to you.