ambiguous call to overloaded function - int and int&

Question

void g(int& a)
{
    std::cout<<\"int&\\n\";
} 

void g(int a)
{
    std::cout<<\"int\\n\";
}  

int main()
{    
    int a = 2;   
    g(a); //w         


        

Answer 1

If you can cast, there is, of course a way to disambiguate the call:

g(const_cast(a));

If you insist to call the reference version, the resolution is a bit more tricky:

static_cast(g)(a);