Char array initialization dilemma

Question

Consider following code:

// hacky, since \"123\" is 4 chars long (including terminating 0)
char symbols[3] = \"123\";

// clean, but lot of typing
char symbo         


        

Answer 1

If your array is only 3 chars long, the first line of code is identical to the second line. The '\0' at the end of the string will simply not be stored. IOW, there is nothing "dirty" or "wrong" with it.