Let\'s say I have the following data frame:
ID Code
1 1 A
2 1 B
3 1 C
4 2 B
5 2 C
6 2 D
7 3 C
8 3 A
9 3 D
10
Here is a data.table way to solve the problem. Use combn function to pick up all possible combinations of Code and then count ID for each unique CodeComb:
library(data.table)
setDT(df)[, .(CodeComb = sapply(combn(Code, 2, simplify = F),
function(cmb) paste(sort(cmb), collapse = ", "))), .(ID)]
# list all combinations of Code for each ID
[, .(IdCount = .N), .(CodeComb)]
# count number of unique id for each code combination
# CodeComb IdCount
# 1: A, B 2
# 2: A, C 2
# 3: B, C 3
# 4: B, D 3
# 5: C, D 2
# 6: A, D 1