Order of evaluation of arguments using std::cout

Question

Hi all I stumbled upon this piece of code today and I am confused as to what exactly happens and more particular in what order :

Code :

#include &l         


        

Answer 1

The order of evaluation is unspecified, see http://en.wikipedia.org/wiki/Sequence_point

This is the same situation as the example with the operator+ example:

Consider two functions f() and g(). In C and C++, the + operator is not associated with a sequence point, and therefore in the expression f()+g() it is possible that either f() or g() will be executed first.