Is there a way to skip the first line of a CSV file and make the second line act as the header?
I have a CSV file that has the date on the first row and the headers
Depending on your data you may use another approach with theskip_lines-option
This examples skip all lines with a leading #
require 'csv'
CSV.parse(DATA.read,:col_sep=>';',:headers=>true,
:skip_lines=> /^#/ #Mark comments!
) do |row|
p row
end
#~
__END__
#~ Comment
#~ More comment
a;b;c;d
1;2;3;4
#~ More comment
1;2;3;4
#~ More comment
1;2;3;4
The result is
#
#
#
In your case the csv contains a date, so you may use:
require 'csv'
CSV.parse(DATA.read,:col_sep=>';',:headers=>true,
:skip_lines=> /^\d\d\d\d-\d\d-\d\d$/ #Skip line with date only
) do |row|
p row
end
#~
__END__
2016-03-19
a;b;c;d
1;2;3;4
1;2;3;4
1;2;3;4
or you could use more extend starting lines:
require 'csv'
CSV.parse(DATA.read,:col_sep=>';',:headers=>true,
:skip_lines=> /^Created by/ #Skip line with date only
) do |row|
p row
end
__END__
Created by test.rb on 2016-03-19
a;b;c;d
1;2;3;4
1;2;3;4
1;2;3;4