#define MIN(A,B) ((A) <= (B) ? (A) : (B))
this is the macro , I was asked what\'s the side effect if I used the following :
lea
Assume initial address of p = 0xfcf0, *p = 1, b = 2, value @ 0xfcf4 = 5 and value @ 0xfcf8 = 15
The macro will expand as
least = ((*p++) <= (b) ? (*p++) : (b));
i.e least = ((1) <= (2) ? (*p++) : (b));
since *p is incremented twice.
1) *p++ --> now p will point to address 0xfcf4;
2) *p++ --> now p will point to address 0xfcf8;
So least = 15; (the values in the address 0xfcf8). Hope it helps.