many options
if ([0, 1, 3, 4, 17, 80].indexOf(x) > 0)
if(/^(1|3|4|17|80)$/.test(x))
if($.inArray(x, [1, 3, 4, 17, 80])
another one, based on Ed's answer
function list() {
for (var i = 0, o = {}; i < arguments.length; i++)
o[arguments[i]] = '';
return o;
}
if(x in list(1, 3, 4, 17, 80))...