Char array subscript warning

Question

when I use char array subscript as in this example:

int main(){
    char pos=0;
    int array[100]={};

    for(pos=0;pos<100;pos++)
        printf(\"%i\\         


        

Answer 1

Because native char can be either unsigned or signed.

Note that it's perfect legal to use negative subscript. For instance:

int arr[10];
int *ptr = arr[5];

Now I can use ptr[-1] which is equivalent to arr[4]. If char happens to be unsigned in the implementation, it can never be a negative value.