How to stringify an expression in C

Question

Is there a way to evaluate an expression before stringification in c?

example:

#define stringify(x)  #x
...
const char * thestring = stringify( 10 *          


        

Answer 1

The C preprocessor cannot do that, so use snprintf instead:

char *stringify(int n) {
   char *res = malloc(12);
   snprintf(res, 12, "%d", n);
   return res;
}

Usage

const char *thestring = stringify(10 * 50);

NB

For simplicity's sake I've omitted error control and free.