Why is the same value output for A[0], &A, and *A?

Question

I am doing a little experiment.

#include
#include
using namespace std;
int main()
{

  int A[5][5];
  cout<

        

Answer 1

A[0] This equivalent to *(A + 0), or more simply *A.

&A is a little more tricky. A is of type int[5][5], which is represented by a continous region of 100 bytes on the stack. The address of A is the start of that region - which is equal to the pointer to the first element. That first elements adress is also the storage location of *A.