Sum of Squares using Haskell

Question

I\'m trying to carry out the following computation: sum of the squares of integers in the range x:y where (x <= y).

I\'m not sure how to put a constraint to ensur

Answer 1

In GHCI do these steps to see what's going on:

Prelude> let sq x = x^2
Prelude> let list = [1..5]
Prelude> list
[1,2,3,4,5]
Prelude> let listOfSq = map sq list
Prelude> listOfSq
[1,4,9,16,25]

Prelude> sum listOfSq
55

The shorthand would be exactly what Jubobs suggested:

sum $ map (^2) [1..5]

EDIT: To error out when Y is greater than X you can do something like this

sumOfSquares :: Integer -> Integer -> Integer
sumOfSquares x y  | y <= x = error "Y must be greater than X"
                  | otherwise = sum $ map (^2) [x..y]