How to run Gulp tasks sequentially one after the other

Question

in the snippet like this:

gulp.task \"coffee\", ->
    gulp.src(\"src/server/**/*.coffee\")
        .pipe(coffee {bare: true}).on(\"error\",gutil.log)
           


        

Answer 1

For me it was not running the minify task after concatenation as it expects concatenated input and it was not generated some times.

I tried adding to a default task in execution order and it didn't worked. It worked after adding just a return for each tasks and getting the minification inside gulp.start() like below.

/**
* Concatenate JavaScripts
*/
gulp.task('concat-js', function(){
    return gulp.src([
        'js/jquery.js',
        'js/jquery-ui.js',
        'js/bootstrap.js',
        'js/jquery.onepage-scroll.js',
        'js/script.js'])
    .pipe(maps.init())
    .pipe(concat('ux.js'))
    .pipe(maps.write('./'))
    .pipe(gulp.dest('dist/js'));
});

/**
* Minify JavaScript
*/
gulp.task('minify-js', function(){
    return gulp.src('dist/js/ux.js')
    .pipe(uglify())
    .pipe(rename('ux.min.js'))
    .pipe(gulp.dest('dist/js'));
});

gulp.task('concat', ['concat-js'], function(){
   gulp.start('minify-js');
});

gulp.task('default',['concat']); 

Source http://schickling.me/synchronous-tasks-gulp/