How to run Gulp tasks sequentially one after the other

Question

in the snippet like this:

gulp.task \"coffee\", ->
    gulp.src(\"src/server/**/*.coffee\")
        .pipe(coffee {bare: true}).on(\"error\",gutil.log)
           


        

Answer 1

I was searching for this answer for a while. Now I got it in the official gulp documentation.

If you want to perform a gulp task when the last one is complete, you have to return a stream:

gulp.task('wiredep', ['dev-jade'], function () {
    var stream = gulp.src(paths.output + '*.html')
        .pipe($.wiredep())
        .pipe(gulp.dest(paths.output));

    return stream; // execute next task when this is completed
});

// First will execute and complete wiredep task
gulp.task('prod-jade', ['wiredep'], function() {
    gulp.src(paths.output + '**/*.html')
        .pipe($.minifyHtml())
        .pipe(gulp.dest(paths.output));
});