Say I have a function called multiplyDivide
If I were to call multiplyDivide(2)(3)(4)(6) it would be equivalent to 2 * 3 / 4 * 6
This is in fact a very good question...
Currying is one of the most fundamental aspects of functional programming languages where you can pass around and return functions. JS being a functional programming language at some level, should be able to perform this operation.
So just like the one in your question one might want to curry an indefinitely many argument function for this or that reasons.
OK let your function be
function multiplyDivide (n,m,o,p){
return n * m / o * p;
}
Then a way of implementing a utility curry function to obtain the curried version of any given function would be as follows;
var curry = f => f.length ? (...a) => curry(f.bind(f,...a)) : f(),
So let's see it in action
function multiplyDivide (n,m,o,p){
return n * m / o * p;
}
var curry = f => f.length ? (...a) => curry(f.bind(f,...a)) : f(),
f = curry(multiplyDivide);
res1 = f(4,5,2,10),
res2 = f(4)(5,2,10),
res3 = f(4)(5)(2,10),
res4 = f(4)(5)(2)(10),
res5 = f(4,5)(2,10),
res6 = f(4,5)(2)(10),
res7 = f(4,5,2)(10),
res8 = f(4,5)(2,10);
console.log(res1,res2,res3,res4,res5,res6,res7,res8);
There might be simpler ways but this is what i could have come up with.