sizeof array clarification

Question

I am studying for a final tomorrow in C, and have a question regarding the sizeof operator.

Let\'s say the size of an int is 32 bits and a

Answer 1

Because zip is an array and the compiler knows its size at compile-time. It just a case of using the same notation for two different things, something quite usual in C.

int
foo (int zap[])

is completely equivalent to

int
foo (int *zap)

The compiler doesn't have any idea how big zap could be (so it leaves the task of finding out to the programmer).