static initialization order fiasco

Question

I was reading about SIOF from a book and it gave an example :

//file1.cpp
extern int y;
int x=y+1;

//file2.cpp
extern int x;
int y=x+1;  

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Answer 1

The initialization steps are given in 3.6.2 "Initialization of non-local objects" of the C++ standard:

Step 1: x and y are zero-initialized before any other initialization takes place.

Step 2: x or y is dynamically initialized - which one is unspecified by the standard. That variable will get the value 1 since the other variable will have been zero-initialized.

Step 3: the other variable will be dynamically initialized, getting the value 2.