Regex pattern inside SQL Replace function?

Question

SELECT REPLACE(\'100.00 GB\', \'%^(^-?\\d*\\.{0,1}\\d+$)%\', \'\');

I want to replace any markup between two

Answer 1

I think a simpler and faster approach is iterate by each character of the alphabet:

DECLARE @i int
SET @i = 0

WHILE(@i < 256)
BEGIN  

    IF char(@i) NOT IN ('0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '.')      

      UPDATE Table SET Column = replace(Column, char(@i), '')

    SET @i = @i + 1

END