Do math functions of constant expressions get pre-calculated at compile time?

Question

I tend to use math functions of constant expressions for convinience and coherence (i.e log(x)/log(2) instead of log(x)/0.3...). Since these functi

Answer 1

It depends on the compiler and the optimization flags. As @AndrewyT points out, GCC has the ability to specify which functions are constant and pure via attributes, and in this case the answer is positive, it will inline the result, as you can easily check:

$ cat constant_call_opt.c 
#include 

float foo() {
        return log(2);
}

$ gcc -c constant_call_opt.c -S

$ cat constant_call_opt.s 
        .file   "constant_call_opt.c"
        .text
.globl foo
        .type   foo, @function
foo:
        pushl   %ebp
        movl    %esp, %ebp
        subl    $4, %esp
        movl    $0x3f317218, %eax
        movl    %eax, -4(%ebp)
        flds    -4(%ebp)
        leave
        ret
        .size   foo, .-foo
        .ident  "GCC: (Ubuntu 4.3.3-5ubuntu4) 4.3.3"
        .section        .note.GNU-stack,"",@progbits

no function call there, just loads a constant (0x3f317218 == 0.69314718246459961 == log(2))

Althought I have not any other compiler at hand to try now, I think you could expect the same behaviour in all the major C compilers out there, as it's a trivial optimization.