I have this regex to allow for only alphanumeric characters.
How can I check that the string at least contains 3 alphabet characters as well.
My current rege
To enforce three alphabet characters anywhere,
/(.*[a-z]){3}/i
should be sufficient.
Edit. Ah, you'ved edited your question to say the three alphabet characters must be consecutive. I also see that you may want to enforce that all characters should match one of your "accepted" characters. Then, a lookahead may be the cleanest solution:
/^(?.*[a-z]{3})[a-z0-9]+$/i
Note that I am using the case-insensitive modifier /i in order to avoid having to write a-zA-Z.
Alternative. You can read more about lookaround assertions here. But it may be a little bit over your head at this stage. Here's an alternative that you may find easier to break down in terms of what you already know:
/^([a-z0-9]*[a-z]){3}[a-z0-9]*$/i