How can I view the contents of a prepared statement?

Question

I\'m working on learning to use prepared statements with mysqli in PHP and usually, if I\'m having a problem with a query I just echo it to the screen to see what it looks l

Answer 1

I usually do this when I need to debug a prepared sql with parameters.

Example of prepare and execute:

$sql = "SELECT VAL1, VAL2 FROM TABLE(?, '?', '?', '?', '?', ?, '?', '?', '?')";
$prep = ibase_prepare( $sql ) or die("Error");
$query = ibase_execute($prep, $param1, $param2, .....) or $err = true;
                              ^^^^^^^^^^^^^^^^^^^^^^^

The easy way to debug the resulting SQL of the sentence it's:

printf( str_replace('?', '%s', $sql), $param1, $param2, ....);
                                      ^^^^^^^^^^^^^^^^^^^^^^

You only need to do one printf, replacing the ? on the prepared SQL string by one %s. printf will interpret all as one string, taking each parameter as placing it on each replaced %s.