Convert hex string (char []) to int?

Question

I have a char[] that contains a value such as \"0x1800785\" but the function I want to give the value to requires an int, how can I convert this to an int? I have searched a

Answer 1

i have done a similar thing, think it might help u its actually working for me

int main(){ int co[8],i;char ch[8];printf("please enter the string:");scanf("%s",ch);for(i=0;i<=7;i++){if((ch[i]>='A')&&(ch[i]<='F')){co[i]=(unsigned int)ch[i]-'A'+10;}else if((ch[i]>='0')&&(ch[i]<='9')){co[i]=(unsigned int)ch[i]-'0'+0;}}

here i have only taken a string of 8 characters. if u want u can add similar logic for 'a' to 'f' to give their equivalent hex values,i haven't done that cause i didn't needed it.