how to convert double between host and network byte order?

Question

Could somebody tell me how to convert double precision into network byte ordering. I tried

uint32_t htonl(uint32_t hostlong);
uint16_t htons(uint16_t hostsh         


        

Answer 1

This might be hacky (the char* hack), but it works for me:

double Buffer::get8AsDouble(){

    double little_endian = *(double*)this->cursor;

    double big_endian;

    int x = 0;
    char *little_pointer = (char*)&little_endian;
    char *big_pointer = (char*)&big_endian;

    while( x < 8 ){
        big_pointer[x] = little_pointer[7 - x];
        ++x;
    }

    return big_endian;

}

For brevity, I've not include the range guards. Though, you should include range guards when working at this level.