Passing an array by reference

Question

How does passing a statically allocated array by reference work?

void foo(int (&myArray)[100])
{
}

int main()
{
    int a[100];
    foo(a);
}
         


        

Answer 1

The following creates a generic function, taking an array of any size and of any type by reference:

template
void my_func(T (&arr)[S]) {
   // do stuff
}

play with the code.