Why widening beats both Boxing and var-args in Overloading of a method?

Question

I am preparing for a SCJP exam and when studying widening part it\'s given that widening beats both Boxing and Var-args in overloading but there is no clear explanation. Tri

Answer 1

class Widen {
    private static widen(long k) {
        System.out.println("Converted to long: " + k);
    }
    private static widen(int ... k) {
        System.out.println("Converted to varargs: " + k);
    }
    private static widen(Integer k) {
        System.out.println("Converted to Integer: " + k);
    }
    public static void main(String ... args) {
        int value = 3;
        widen(value);  // Output: Converted to long: 3
    }
} 

to solve above mind this:

widening beats boxing, boxing beats varargs

the out put will be Converted to long:3