Why widening beats both Boxing and var-args in Overloading of a method?

Question

I am preparing for a SCJP exam and when studying widening part it\'s given that widening beats both Boxing and Var-args in overloading but there is no clear explanation. Tri

Answer 1

The compiler has to keep compatibility with previous versions of Java. On top of that the compiler chooses the most performant / smallest change to the argument. Promoting to another primitive beats creating wrapper object and that beats creating an array with regards to memory usage and performance.