Repeat Character N Times

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栀梦
栀梦 2020-11-22 11:51

In Perl I can repeat a character multiple times using the syntax:

$a = \"a\" x 10; // results in \"aaaaaaaaaa\"

Is there a simple way to ac

23条回答
  •  庸人自扰
    2020-11-22 12:15

    The most performance-wice way is https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/repeat

    Short version is below.

      String.prototype.repeat = function(count) {
        if (count < 1) return '';
        var result = '', pattern = this.valueOf();
        while (count > 1) {
          if (count & 1) result += pattern;
          count >>>= 1, pattern += pattern;
        }
        return result + pattern;
      };
      var a = "a";
      console.debug(a.repeat(10));
    

    Polyfill from Mozilla:

    if (!String.prototype.repeat) {
      String.prototype.repeat = function(count) {
        'use strict';
        if (this == null) {
          throw new TypeError('can\'t convert ' + this + ' to object');
        }
        var str = '' + this;
        count = +count;
        if (count != count) {
          count = 0;
        }
        if (count < 0) {
          throw new RangeError('repeat count must be non-negative');
        }
        if (count == Infinity) {
          throw new RangeError('repeat count must be less than infinity');
        }
        count = Math.floor(count);
        if (str.length == 0 || count == 0) {
          return '';
        }
        // Ensuring count is a 31-bit integer allows us to heavily optimize the
        // main part. But anyway, most current (August 2014) browsers can't handle
        // strings 1 << 28 chars or longer, so:
        if (str.length * count >= 1 << 28) {
          throw new RangeError('repeat count must not overflow maximum string size');
        }
        var rpt = '';
        for (;;) {
          if ((count & 1) == 1) {
            rpt += str;
          }
          count >>>= 1;
          if (count == 0) {
            break;
          }
          str += str;
        }
        // Could we try:
        // return Array(count + 1).join(this);
        return rpt;
      }
    }
    

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