awk extract multiple groups from each line

后端 未结 4 2207
盖世英雄少女心
盖世英雄少女心 2020-12-06 12:51

How do I perform action on all matching groups when the pattern matches multiple times in a line?

To illustrate, I want to search for /Hello! (\\d+)/ an

4条回答
  •  一生所求
    2020-12-06 13:02

    There is no gawk function to match the same pattern multiple times in a line. Unless you know exactly how many times the pattern repeats.

    Having this, you have to iterate "manually" on all matches in the same line. For your example input, it would be:

    {
      from = 0
      pos = match( $0, /Hello! ([0-9]+)/, val )
      while( 0 < pos )
      {
        print val[1]
        from += pos + val[0, "length"]
        pos = match( substr( $0, from ), /Hello! ([0-9]+)/, val )
      }
    }
    

    If the pattern shall match over a linefeed, you have to modify the input record separator - RS

提交回复
热议问题