awk extract multiple groups from each line

Question

How do I perform action on all matching groups when the pattern matches multiple times in a line?

To illustrate, I want to search for /Hello! (\\d+)/ an

Answer 1

This is a simple syntax, and every awk (nawk, mawk, gawk, etc) can use this.

{
    while (match($0, /Hello! [0-9]+/)) {
        pattern = substr($0, RSTART, RLENGTH);
        sub(/Hello! /, "", pattern);
        print pattern;
        $0 = substr($0, RSTART + RLENGTH);
    }
}