Catch multiple exceptions at once?

Question

It is discouraged to simply catch System.Exception. Instead, only the "known" exceptions should be caught.

Now, this sometimes leads to unnecce

Answer 1

I want to suggest shortest answer (one more functional style):

        Catch(() =>
            {
                WebId = new Guid(queryString["web"]);
            },
            exception =>
            {
                WebId = Guid.Empty;
            });

For this you need to create several "Catch" method overloads, similar to System.Action:

    [DebuggerNonUserCode]
    public static void Catch(Action tryBlock,
        Action catchBlock)
    {
        CatchMany(tryBlock, catchBlock, typeof(TException1), typeof(TException2));
    }

    [DebuggerNonUserCode]
    public static void Catch(Action tryBlock,
        Action catchBlock)
    {
        CatchMany(tryBlock, catchBlock, typeof(TException1), typeof(TException2), typeof(TException3));
    }

and so on as many as you wish. But you need to do it once and you can use it in all your projects (or, if you created a nuget package we could use it too).

And CatchMany implementation:

    [DebuggerNonUserCode]
    public static void CatchMany(Action tryBlock, Action catchBlock,
        params Type[] exceptionTypes)
    {
        try
        {
            tryBlock();
        }
        catch (Exception exception)
        {
            if (exceptionTypes.Contains(exception.GetType())) catchBlock(exception);
            else throw;
        }
    }

p.s. I haven't put null checks for code simplicity, consider to add parameter validations.

p.s.2 If you want to return a value from the catch, it's necessary to do same Catch methods, but with returns and Func instead of Action in parameters.