LINQ swap columns into rows

Question

Is there a fancy LINQ expression that could allow me to do the following in a much more simpler fashion. I have a List>, assuming the L

Answer 1

var inverted = Enumerable.Range(0, columnCount)
               .Select(index => columnList.Select(list => list[index]));

In short, we enumerate the column index from a range and use it to collect the nth element of each list.

Please note that you'll need to check that every list has the same number of columns.