Modifying String Literal [duplicate]

Answer 1

There are several other problems with your code.

1. Pointers are usually used to point to data that already exists, so you can use it like this

   char arr[] = "C++";

   char* t = &arr[0];

Also modifiable,

t[1] = 'p';

t[2] = 'p';

of course there is a special way of using string —— let the pointer point to a string constant. Just the way you used:

char *t = "C++";   // you cannot modify it in most operating systems
t[1] = 'p';
t[2] = 'p';

There is a better way of using it, which is more portable and easy to understand:

const char* t="C++"; 

2.You code have many place that is not in c standard

#include  // You'd better add a space between, for this is a good coding convention
#include  // only supported by vc/vs in windows, you can use getchar() instead

int main()  // main returns int
{
    char* t = "C++";

    t[1] = 'p';
    t[2] = 'p';
    printf("%s\n", t);  // it's a good habit to add a '\n' when printing a string
    getchar();   // getchar() is supported by c standard library 

    return 0; // return 0 here
}

3.about printing string

Linux is line-buffered(ignore this if you are using windows :P) & for easier to read in console, you'd better add a '\n' at the end of you printed string:

printf("%s\n",t);

If you don't want to have a carriage return after a string. In windows use just as you like:

printf("%s",t);

In Linux, you should add a fflush() in stdlib.h.

printf("%s",t);
fflush(stdout);