why typeid returns that int and const int are same types

Question

if(typeid(int) == typeid(const int))
       cout << \"Same types\"<< endl;

PROGRAM OUTPUT:

Same

Answer 1

They aren't the same type, but the typeid operator strips const and volatile.

From section 5.2.8 [expr.typeid]:

The top-level cv-qualifiers of the glvalue expression or the type-id that is the operand of typeid are always ignored.