I know I can write a query that will return all rows that contain any number of values in a given column, like so:
Select * from tbl where my_col in (val1, v
select * from tbl
where my_col like '%val1%' or my_col like'%val2%' or my_col like '%val3%', ...
But beware, that might be quite slow... Alternatively, you could insert all acceptable values (including % signs) into a table and semi-join that table:
select * from tbl
where exists (select 1 from all_likes where tbl.my_col like all_likes.value)
For true full-text search, you might want to look at Oracle Text:
http://www.oracle.com/technetwork/database/enterprise-edition/index-098492.html