Always Round UP a Double

Question

How could I always round up a double to an int, and never round it down. I know of Math.round(double), but I want it to always round u

Answer 1

Short example without using Math.ceil().

public double roundUp(double d){
    return d > (int)d ? (int)d + 1 : d;
}

Exaplanation: Compare operand to rounded down operand using typecast, if greater return rounded down argument + 1 (means round up) else unchanged operand.

Example in Pseudocode

double x = 3.01
int roundDown = (int)x   // roundDown = 3
if(x > roundDown)        // 3.01 > 3
    return roundDown + 1 // return 3.0 + 1.0 = 4.0
else
    return x             // x equals roundDown

Anyway you should use Math.ceil(). This is only meant to be a simple example of how you could do it by yourself.