How to get the sum of timedelta in Python?

Question

Python: How to get the sum of timedelta?

Eg. I just got a lot of timedelta object, and now I want the sum. That\'s it!

Answer 1

I am pretty sure that by "sum" he means that he wants the value of the sum in a primitive type (eg integer) rather than a datetime object.

Note that you can always use the dir function to reflect on an object, returning a list of its methods and attributes.

>>> import datetime
>>> time_sum=datetime.timedelta(seconds=10) + datetime.timedelta(hours=5)
>>> time_sum
datetime.timedelta(0, 18010)
>>> dir(time_sum)
['__abs__', '__add__', '__class__', '__delattr__', '__div__', '__doc__', '__eq__', '__floordiv__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__mul__', '__ne__', '__neg__', '__new__', '__nonzero__', '__pos__', '__radd__', '__rdiv__', '__reduce__', '__reduce_ex__', '__repr__', '__rfloordiv__', '__rmul__', '__rsub__', '__setattr__', '__str__', '__sub__', 'days', 'max', 'microseconds', 'min', 'resolution', 'seconds']

So in this case, it looks like we probably want seconds.

>>> time_sum.seconds
18010

Which looks right to me:

>>> 5*60*60 + 10
18010