Why are integer types promoted during addition in C?

Question

So we had a field issue, and after days of debugging, narrowed down the problem to this particular bit of code, where the processing in a while loop wasn\'t happening :

Answer 1

Literal 1 in of int, i.e. in your case int32 type, so operations with int32 and int16 give results of int32.

To have result of numberA + 1 statement as uint16_t try explicit type cast for 1, e.g.: numberA + (uint16_t)1