Does one double promote every int in the equation to double?

Question

Does the presence of one floating-point data type (e.g. double) ensure that all +, -, *, /, %, etc math operations assume double operands?

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Answer 1

Does one double promote every int in the equation to double?

No. Only the result of a single operation (with respect to precedence).

double result1 = a + b/d + c; // equal to 4 or to 4.5?

4.5.

double result2 = (a + b)/d + c; // equal to 3 or to 3.75?

3.75.

double result3 = a/b + d; // equal to 4 or to 4.5?

4.