Get browser version using selenium webdriver

Question

How would I get the browser version being used?

>>> from selenium import webdriver
>>> driver = webdriver.Firefox()
>>> print vers         


        

Answer 1

You can extract the browser version of the GeckoDriver initiated firefox session by accessing the capabilities object which returns a dictionary and you can use the following solution:

from selenium import webdriver
from selenium.webdriver.firefox.options import Options

options = Options()
options.binary_location = r'C:\Program Files\Mozilla Firefox\firefox.exe'
driver = webdriver.Firefox(firefox_options=options, executable_path=r'C:\WebDrivers\geckodriver.exe')
my_dict = driver.capabilities
print("Mozilla Firefox browser version is: " + str(my_dict['browserVersion']))
driver.quit()

Console Output:

Mozilla Firefox browser version is: 77.0.1

---

Extracting all the capabilities

Likewise, you can extract all the properties from the dictionary as follows:

from selenium import webdriver
from selenium.webdriver.firefox.options import Options

options = Options()
options.binary_location = r'C:\Program Files\Mozilla Firefox\firefox.exe'
driver = webdriver.Firefox(firefox_options=options, executable_path=r'C:\WebDrivers\geckodriver.exe')
my_dict = driver.capabilities
for key,val in my_dict.items():
    print (key, "=>", val)
driver.quit()

Console Output:

acceptInsecureCerts => True
browserName => firefox
browserVersion => 77.0.1
moz:accessibilityChecks => False
moz:buildID => 20200602222727
moz:geckodriverVersion => 0.26.0
moz:headless => False
moz:processID => 12668
moz:profile => C:\Users\Soma Bhattacharjee\AppData\Local\Temp\rust_mozprofileFc1B08
moz:shutdownTimeout => 60000
moz:useNonSpecCompliantPointerOrigin => False
moz:webdriverClick => True
pageLoadStrategy => normal
platformName => windows
platformVersion => 10.0
rotatable => False
setWindowRect => True
strictFileInteractability => False
timeouts => {'implicit': 0, 'pageLoad': 300000, 'script': 30000}
unhandledPromptBehavior => dismiss and notify