The powerset of {1, 2, 3}
is:
{{}, {2}, {3}, {2, 3}, {1, 2}, {1, 3}, {1, 2, 3}, {1}}
Let\'s say I have a Set
in Java:<
Yet another solution - with java8+ streaming api It is lazy and ordered so it returns correct subsets when it is used with "limit()".
public long bitRangeMin(int size, int bitCount){
BitSet bs = new BitSet(size);
bs.set(0, bitCount);
return bs.toLongArray()[0];
}
public long bitRangeMax(int size, int bitCount){
BitSet bs = BitSet.valueOf(new long[]{0});
bs.set(size - bitCount, size);
return bs.toLongArray()[0];
}
public Stream> powerSet(Collection data)
{
List list = new LinkedHashSet<>(data).stream().collect(Collectors.toList());
Stream head = LongStream.of(0).mapToObj( i -> BitSet.valueOf(new long[]{i}));
Stream tail = IntStream.rangeClosed(1, list.size())
.boxed()
.flatMap( v1 -> LongStream.rangeClosed( bitRangeMin(list.size(), v1), bitRangeMax(list.size(), v1))
.mapToObj(v2 -> BitSet.valueOf(new long[]{v2}))
.filter( bs -> bs.cardinality() == v1));
return Stream.concat(head, tail)
.map( bs -> bs
.stream()
.mapToObj(list::get)
.collect(Collectors.toList()));
}
And the client code is
@Test
public void testPowerSetOfGivenCollection(){
List data = new LinkedList<>();
for(char i = 'a'; i < 'a'+5; i++ ){
data.add(i);
}
powerSet(data)
.limit(9)
.forEach(System.out::print);
}
/* Prints : [][a][b][c][d][e][a, b][a, c][b, c] */