In SQL Server, how do I generate a CREATE TABLE statement for a given table?

Question

I\'ve spent a good amount of time coming up with solution to this problem, so in the spirit of this post, I\'m posting it here, since I think it might be useful to others. <

Answer 1

I'm going to improve the answer by supporting partitioned tables:

find partition scheme and partition key using below scritps:

declare @partition_scheme varchar(100) = (
select distinct ps.Name AS PartitionScheme
from sys.indexes i  
join sys.partitions p ON i.object_id=p.object_id AND i.index_id=p.index_id  
join sys.partition_schemes ps on ps.data_space_id = i.data_space_id  
where i.object_id = object_id('your table name')
)
print @partition_scheme

declare @partition_column varchar(100) = (
select c.name 
from  sys.tables          t
join  sys.indexes         i 
      on(i.object_id = t.object_id 
  and i.index_id < 2)
join  sys.index_columns  ic 
  on(ic.partition_ordinal > 0 
  and ic.index_id = i.index_id and ic.object_id = t.object_id)
join  sys.columns         c 
  on(c.object_id = ic.object_id 
  and c.column_id = ic.column_id)
where t.object_id  = object_id('your table name')
)
print @partition_column

then change the generation query by adding below line at the right place:

+ IIF(@partition_scheme is null, '', 'ON [' + @partition_scheme + ']([' + @partition_column + '])')