Sort array of objects by single key with date value

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情话喂你
情话喂你 2020-11-22 10:56

I have an array of objects with several key value pairs, and I need to sort them based on \'updated_at\':

[
    {
        \"updated_at\" : \"2012-01-01T06:25         


        
19条回答
  •  面向向阳花
    2020-11-22 11:55

    Sorting by an ISO formatted date can be expensive, unless you limit the clients to the latest and best browsers, which can create the correct timestamp by Date-parsing the string.

    If you are sure of your input, and you know it will always be yyyy-mm-ddThh:mm:ss and GMT (Z) you can extract the digits from each member and compare them like integers

    array.sort(function(a,b){
        return a.updated_at.replace(/\D+/g,'')-b.updated_at.replace(/\D+/g,'');
    });
    

    If the date could be formatted differently, you may need to add something for iso challenged folks:

    Date.fromISO: function(s){
        var day, tz,
        rx=/^(\d{4}\-\d\d\-\d\d([tT ][\d:\.]*)?)([zZ]|([+\-])(\d\d):(\d\d))?$/,
        p= rx.exec(s) || [];
        if(p[1]){
            day= p[1].split(/\D/).map(function(itm){
                return parseInt(itm, 10) || 0;
            });
            day[1]-= 1;
            day= new Date(Date.UTC.apply(Date, day));
            if(!day.getDate()) return NaN;
            if(p[5]){
                tz= (parseInt(p[5], 10)*60);
                if(p[6]) tz+= parseInt(p[6], 10);
                if(p[4]== '+') tz*= -1;
                if(tz) day.setUTCMinutes(day.getUTCMinutes()+ tz);
            }
            return day;
        }
        return NaN;
    }
    if(!Array.prototype.map){
        Array.prototype.map= function(fun, scope){
            var T= this, L= T.length, A= Array(L), i= 0;
            if(typeof fun== 'function'){
                while(i< L){
                    if(i in T){
                        A[i]= fun.call(scope, T[i], i, T);
                    }
                    ++i;
                }
                return A;
            }
        }
    }
    }
    

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