Function to create in-memory zip file and return as http response

Question

I am avoiding the creation of files on disk, this is what I have got so far:

def get_zip(request):
    import zipfile, StringIO
    i = open(\'picture.jpg\',         


        

Answer 1

Avoiding disk files can slow your server to a crawl, but it will certainly work.

You'll exhaust memory if you serve too many of these requests concurrently.