Function overloading — two functions only differ by a default parameter

Question

class A{
    public:
        void foo(int x)
        {
            cout << \"foo with one\\n\";
        }

        void foo(int x, int y=10)
        {
                 


        

Answer 1

Why not?

class A{
    public:

        void foo(int x=10, int y=10)
        {
            cout << "foo with two\n";
        }
};