Sort an array in the same order of another array

Question

I have a few arrays of 50+ names like this.

[\"dan\", \"ryan\", \"bob\", \"steven\", \"corbin\"]
[\"bob\", \"dan\", \"steven\", \"corbin\"]

Answer 1

I had the same issue now and I tried a bit different approach. It does not sort the arrays but filtering the order-list according to sorting-lists so it has got some limitations but for my needs it's event better because it gets rid of incorrect values from sorted list:

• if sorting-list has got doubled value, it will occure just once in sorted list
• if sorting-list has got item which is not included in order-list, it will not appear in sorted list

function sortOrder(getOrder,getArr){
  return getOrder.filter(function(order){
    return getArr.some(function(list){
      return order === list;
    });
  });
}

//arrays
var order = ["ryan", "corbin", "dan", "steven", "bob"];
var arA = ["dan", "ryan", "bob", "steven", "corbin"];
var arB = ["bob", "dan", "steven", "corbin"];
var arC = ["bob","ryan"];
var arD = ["bob","bob","corbin"]; //remove repetition
var arE = ["unrecognizedItem","corbin","steven","ryan"]; //remove the item not included in order array

//print results
document.body.innerHTML = sortOrder(order,arA)+'
';
document.body.innerHTML += sortOrder(order,arB)+'
';
document.body.innerHTML += sortOrder(order,arC)+'
';
document.body.innerHTML += sortOrder(order,arD)+'
';
document.body.innerHTML += sortOrder(order,arE)+'
';