How can I open the Settings app when the user presses a button?

Question

From what I understand by using code like this:

NSURL* appUrl = [NSURL URLWithString: @\"URL\"];
[[UIApplication sharedApplication] openURL:appUrl];
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Answer 1

Swift 3

private func showAlertPrivacy() {
    let alertController = UIAlertController(title: nil, message: "messagePrivacy", preferredStyle: .alert)
    let alertNo = UIAlertAction(title: "No", style: .default) { (_) in

    }
    alertController.addAction(alertNo)

    let alertSetting = UIAlertAction(title: "Settings", style: .default) { (_) in

        UIApplication.shared.open(URL(string:UIApplicationOpenSettingsURLString)!, options: [:], completionHandler: { (_) in

        })
    }
    alertController.addAction(alertSetting)

    present(alertController, animated: true) { 

    }
}