How to sort Integer digits in ascending order without Strings or Arrays?

Question

I\'m trying to sort the digits of an integer of any length in ascending order without using Strings, arrays or recursion.

Example:

Input: 451467
Outp         


        

Answer 1

Here is the simple solution :

    public class SortDigits
    {
        public static void main(String[] args)
        {
            sortDigits(3413657);
        }

        public static void sortDigits(int num)
        {
            System.out.println("Number  : " + num);
            String number = Integer.toString(num);
            int len = number.length(); // get length of the number
            int[] digits = new int[len];
            int i = 0;
            while (num != 0)
            {
                int digit = num % 10;
                digits[i++] = digit; // get all the digits
                num = num / 10;
            }
            System.out.println("Digit before sorting: ");
            for (int j : digits)
            {
                System.out.print(j + ",");
            }
            sort(digits);
            System.out.println("\nDigit After sorting: ");
            for (int j : digits)
            {
                System.out.print(j + ",");
            }
        }
        //simple bubble sort 
        public static void sort(int[] arr)
        {
            for (int i = 0; i < arr.length - 1; i++)
                for (int j = i + 1; j < arr.length; j++)
                {
                    if (arr[i] > arr[j])
                    {
                        int tmp = arr[j];
                        arr[j] = arr[i];
                        arr[i] = tmp;
                    }
                }
        }
    }