I need to show an image by using the file name only, not from the resource id.
ImageView imgView = new ImageView(this);
imgView.setBackgroundResource(R.drawa
public static Bitmap decodeFile(String path) {
Bitmap b = null;
File f = new File(path);
// Decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
FileInputStream fis = null;
try {
fis = new FileInputStream(f);
BitmapFactory.decodeStream(fis, null, o);
fis.close();
int IMAGE_MAX_SIZE = 1024; // maximum dimension limit
int scale = 1;
if (o.outHeight > IMAGE_MAX_SIZE || o.outWidth > IMAGE_MAX_SIZE) {
scale = (int) Math.pow(2, (int) Math.round(Math.log(IMAGE_MAX_SIZE / (double) Math.max(o.outHeight, o.outWidth)) / Math.log(0.5)));
}
// Decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
fis = new FileInputStream(f);
b = BitmapFactory.decodeStream(fis, null, o2);
fis.close();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return b;
}
public static Bitmap showBitmapFromFile(String file_path)
{
try {
File imgFile = new File(file_path);
if(imgFile.exists()){
Bitmap pic_Bitmap = decodeFile(file_path);
return pic_Bitmap;
}
} catch (Exception e) {
MyLog.e("Exception showBitmapFromFile");
return null;
}
return null;
}
if you are using image loading in List view then use Aquery concept .
https://github.com/AshishPsaini/AqueryExample
AQuery aq= new AQuery((Activity) activity, convertView);
//load image from file, down sample to target width of 250 pixels .gi
File file=new File("//pic/path/here/aaaa.jpg");
if(aq!=null)
aq.id(holder.pic_imageview).image(file, 250);